a. If Re z(it' s real part)=2 and z-i modulus is minimum
b.If img z = -1 and modulus of z-i-1 is minimum.
Thank you very much for any ideea!
Det. z included in C(complex)...?
a. the answer is z = 2 + i.
get the Argand diagram of the complex plane. Re z = 2 means the vertical line x = 2. The point closest to (0,1) is (2,1).
b. Im z = -1... this time we have a horizontal line y = -1.
The point closest to (1,1) is the point (1,-1)
Thus the answer is z = 1 - i.
We can also do the analysis algebraically ... §
for question a.
you already know that z = 2 + bi.
z - i = 2 + (b-1)i
the modulus of that is 2^2 + (b-1)^2 ... the quadratic is minimum if b = 1.
Thus z = 2 + i.
radiata
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