A substance has a specific heat heat capacity of 2.0 J/g.C', how many joules...?

A substance has a specific heat capacity of 2.0 J/g.C', how many joules are needed to raise the temperature of 30.0g of this substance by 15 degrees C?


do i need to include 15 degrees in the equation to solve?

A substance has a specific heat heat capacity of 2.0 J/g.C', how many joules...?
Specific heat capacity, also known simply as specific heat (Symbol: C or c) is the measure of the heat energy required to raise the temperature of a given amount of a substance by one degree. Commonly, the amount is specified by mass; for example, water has a mass-specific heat capacity of about 4184 joules per kelvin per kilogram. Volume-specific and molar-specific heat capacities are also used.





The equation relating heat energy to specific heat capacity, where the unit quantity is in terms of mass is:





Q = m c ΔT





Your substance has specific heat capacity of 2.0 J/(g*°C).





Q = 30.0 (m) * 2.0 (c) * 15 (ΔT) = 900 joules
Reply:. Q = MC ( t2 - t1)


Q= 30 g 2 JouLe/g.C^ (15-0)C^


Q= 60 (15) = 900 JouLes
Reply:Yes, the equation you need is:





Q = m * c * delta T





Where delta T is the temperature change. In this case, 15 degrees.





So...





Q = 30 g * 2 J/gC * 15 C


= 900 J





The units also work out. The C's cancel and the g's cancel leaving you only with J's, which is what you want.





Hope this helps!
Reply:You need to apply 2.0 Joules to heat each gram of the substance by one degree Celcius.





Amount of heat needed = 2 J/gC x 30g x 15C = 900J





So yes, you do need to include the 15 degrees C.


Note that the actual initial temperature is not relevant, only the change.
Reply:2*30*15=900 J
Reply:Energy = mass x heat capacity x (T2 - T1)





mass = 30.0 g


heat capacity = 2.0 Joules / g °C


T2-T1 = 15°C





u do the rest...
Reply:Yes. The equation needed for the problem is q = m * c * delta T


where q is the heat in joules


m is the mass


and delta T is the change in temperature
Reply:Yes, you do need the 15 degrees. I'll solve the whole problem for you.





Q = m.C.deltaT





Where


Q = Heat supplied(which is what we are looking for)


m = mass of object/substance


C = specific heat capacity


deltaT= change in temparature/ temparature difference





NOTE: Im using 'delta' which means 'change' because I cant find the symbol on my keyboard. But the symbol is a triangle before the T i.e. '(delta symbol/triangle)T' meaning change in temparature.





From the question, we are given;


m = 30.0g


C = 2.0J/g.'C


deltaT = 15'C


Q = ?





Since Q = m x C x deltaT





Q = 30.0g x 2.0J/g'C x 15'C.....i


= 900J..................................ii





On step i, the units g and 'C cancel out so that we remain with J (joules), which is the unit for heat/ energy.





The amount of heat(number of joules needed) is 900J.





Do this, there is no way you are getting it wrong
Reply:Q = (m)(delta T)(Cp)


Q = (30.0 g)(15 C - 0 C)(2.0 J/g.C)


Q = (30.0 g)(15 C)(2.0 J/g.C)


Q = 900 J


Account for significant digits


Q = 9.0 * 10^2 J